AARoads Forum
National Boards => General Highway Talk => Topic started by: hbelkins on December 21, 2009, 09:26:08 PM

Anyone remember the Road Sign math site at http://www.roadsignmath.com? It's been dormant for quite awhile.
Maybe we should resurrect the topic here.

sure; this is a good way of bringing in other sign photographs that are not shield related.
here is a rule for continuity ... all posted photos must obey the math rule, as seen on that website, and furthermore one number from the previous photo must appear in the next one.
the math rule, in short, is you have to take a single sign (in our case, let's extend it to a single gantry if you want, as long as all the signs are facing one direction) and using all the numbers exactly once, write an equation that is correct.
I'll start off with something simple.
(http://shields.aaroads.com/img/NB/NB19520021i1.jpg)
9 x 2 = 8 + 10
next poster has to come up with another photo that has at least one 2, 8, 9, or 10, and of course a correct equation. Good good? yes yes.

Where is Carol Vorderman when you need her?

(http://www.gribblenation.net/nyroutes/images/photos/routes/009/00902038s.jpg)
1+1+7=9

So can we break up numbers into their component digits? I got the impression the Road Sign Math site didn't do that.

(http://i572.photobucket.com/albums/ss166/xonhulu/Oregon%20State%20Routes/057.jpg?t=1267579697)
O.k., this took some figuring but I finally figured it out:
sqrt((sqrt(82101/101))!/(sqrt(59+5))!)=21/sqrt(47+2)

So can we break up numbers into their component digits? I got the impression the Road Sign Math site didn't do that.
for now, let's go with all numbers to be treated as they are, but if we have trouble coming up with examples (the Road Sign Math site hasn't been able to find one in two years :D) then we can relax the rules.

Road Sign Math didn't require the "use a number in the previous example" bit, but I understand this site is a bit different. RSM used to be on some different format but changed to the blogstyle format (I think they use WordPress) shortly before going dormant. And I had a bunch of examples to send to them before they assumed room temperature.

(http://i622.photobucket.com/albums/tt304/24DIDNOTWIN/VA199WESTATVA31ANDVA5EAST.jpg)
55=31(199199)

The above would not work according to http://www.roadsignmath.com/rules/

Thanks for that reference, HB. I see now that my earlier work violated the rules since 101 occurred twice and I used it twice.

Thanks for that reference, HB. I see now that my earlier work violated the rules since 101 occurred twice and I used it twice.
I JUST noticed that 199 the left side of the photo.

Thanks for that reference, HB. I see now that my earlier work violated the rules since 101 occurred twice and I used it twice.
I JUST noticed that 199 the left side of the photo.
I just realized I did an epic fail too

(http://www.gribblenation.net/nyroutes/images/photos/routes/016/01606891s.jpg)
7878=16*(2020)

Thanks for that reference, HB. I see now that my earlier work violated the rules since 101 occurred twice and I used it twice.
O.k. I just reread the rules and saw that I actually should have used 101 twice since it appeared twice in the photo, so my math did follow the rules.
No putdown to WNYroadgeek and 74/171FAN, but you both used basically the same formula ( aa = c(bb) ) and this will always work on any assembly or sign where two routes are repeated (you can always get 0=0). The same is true in this photo:
(http://i572.photobucket.com/albums/ss166/xonhulu/US%20Routes/US211Warrenton8.jpg)
Now, I could go the 15  15 = 29(211  211) route, but it takes more to see this one: 15 + 15  (211/211) = 29
We should try to be creative and have fun with this game. In fact, this game might be a little more fun if one person posts a sign and have others try to find a math equation for it (the poster should already know one exists). Any thoughts?

OK, here's an easy one for you.
(http://www.millenniumhwy.net/2008_Buffalo_Day_2/Images/285.jpg)

1*2^3 + 6 = 14

1*2^3 + 6 = 14
you forgot to solve for N ;)

also, your turn to post a photo. I think this is a good way to ensure continuity...

1*2^3 + 6 = 14
Actually, all numbers used (including the sum) must be included on the sign and all signs must be on the same assembly. That's why, in the RSM game, two or more signs on independent posts wouldn't count unless there was a stabilizing bar installed. I remember submitting a sign to RSM and it being rejected because of this. Then during a sign replacement project, a connecting bar was added and the sign assembly became eligible. There was no 1 or 14 on the sign; I know you got them from the bridge height warning sign in the background but the only eligible numbers were on the BGS. 2 x 3 = 6.
There's another candidate just a few miles up the road from that sign on I90 in Pennsylvania.

Here's another nobrainer :colorful:
(http://www.speedcam.pwp.blueyonder.co.uk/us1214.jpg)

You're probably going for 1 + 1 + 2 = 4, but you can't split numbers up in a sign, according to the original RSM rules. "12" is "12," not "1" and "2."

Ok, but this one works. 39+51=90
(http://www.speedcam.pwp.blueyonder.co.uk/i3990.jpg)

you forgot to solve for N ;)
Cool, because a variable would make all the problems really easy. :nod:
Anyway, you're right, I should post a followup photo. This one has at least one solution, not using 0 = 0:
(http://i572.photobucket.com/albums/ss166/xonhulu/Oregon%20State%20Routes/OR99E211214Woodburn2.jpg?t=1272128230)

211 + (13/13) + (99/99)  2 + 11  8 = 214
not quite 0 = 0 but still a kinda trivial solution involving the 13/13 and 99/99. nowhere near as impressive as that WW2 era OR2/US101 photo!

211 + (13/13) + (99/99)  2 + 11  8 = 214
not quite 0 = 0 but still a kinda trivial solution involving the 13/13 and 99/99. nowhere near as impressive as that WW2 era OR2/US101 photo!
Thanks for the props on that; it took me quite awhile to figure that one out.
Anyway, here's another which is a little more difficult. I assume these two signs function effectively as one assembly...
(http://i572.photobucket.com/albums/ss166/xonhulu/US%20Routes/US197ShanikoJunction10.jpg)

I assume these two signs function effectively as one assembly...
I think that's reasonable, not the extremely anal rules on the RSM site which apparently allowed a submission to hinge on a single structural support bar. Lame.

@_@ *my head hurts looking at all this....havent done serious math outside my tax returns in DECADES!
THUD!!! X_x!!!

@_@ *my head hurts looking at all this....havent done serious math outside my tax returns in DECADES!
THUD!!! X_x!!!
I know. This is totally unfair: I teach math, so those mental muscles have stayed strong.

I never had these skills in the first place :\

No takers? It isn't that horrifically hard...

sqrt(19797)=(2622)+(6862)
Not complicated when you look at it. The fact that 19797 = 100 and all the numbers on top are even is a glaring nudge in the right direction.
This one should be easier:
(http://img36.imageshack.us/img36/2408/dscn5950a.jpg)
That's 1, 7, 87, and 95. Go!

(87+7) = (951)
(http://farm4.static.flickr.com/3504/4020728804_2deb9425ef.jpg)
One of the numbers does not get used  and that number is not a route number

You can use them all: 29 + 81 = 66 + 65 + 1  (10 + 12). Those are the only numbers on the main assembly.
Here's a really hard one also involving US 10 and 12:
(http://i572.photobucket.com/albums/ss166/xonhulu/US%20Routes/US212MilesCity81.jpg?t=1275197794)
O.k., I'm joking. I'm still looking for a good new photo.

All right, here's another. Try to find a solution where you aren't just balancing the identical numbers, there's a more clever equation.
(http://i572.photobucket.com/albums/ss166/xonhulu/US%20Routes/US116Cody1.jpg?t=1267504485)

My first go at one of these...
120/20  (1614) = 120/(16+14)
Unfortunately, I don't have access to any road photos right now as I'm away from my home computer. I invite anyone to post a new photo in my stead.

Good answer, and thanks for sticking with my rules for it!
I'll look for another to post, but it takes awhile, as I have to make sure there is an answer first.

Here's another relatively simple one from I90 in the Keystone State:
(http://www.millenniumhwy.net/2008_Buffalo_Day_2/Images/292.jpg)

I'd solve it, but I can't do math in Clearview. :confused:
Here's another tough one:
(http://i572.photobucket.com/albums/ss166/xonhulu/Interstate%20Routes/I15IdahoFallsexit11311.jpg)

All Clearview jokes aside, 2 x 9 = 18
Try this out:
(http://i957.photobucket.com/albums/ae53/njroadhorse/US%20Route%20501/010.jpg)

No answer yet. We are only using the four numbers (9, 57, 301, 501) on the arm, right? I can solve it using the background shields and speed limit as well, but using any numbers in the background wouldn't be following the rules.
I've got a good one to follow this photo ready to go, but I want to solve this one first.

No answer yet. We are only using the four numbers (9, 57, 301, 501) on the arm, right?
Yeah, just the numbers on the arm.

You'll have to show me your solution, NJRoadhorse; I'm stumped!
Here's that photo I was promising. The WA 12 is an error; it should be US 12.
(http://i572.photobucket.com/albums/ss166/xonhulu/Sign%20Goofs/US12SignGoofFR9925Jct1.jpg?t=1267580743)

Easy enough. 25+5/5+1214=4420
The mast arm one, however, is driving me crazy.

Good job. I'm still stumped on the mast arm problem, too.

(http://www.gribblenation.net/nyends/images/farr/17end54.jpg)
15 + 17 = 86  54

Glad this thread isn't dead. Here's one for someone to crack:
(http://i572.photobucket.com/albums/ss166/xonhulu/Oregon%20State%20Routes/OR103Elsie9.jpg?t=1289793812)

Glad this thread isn't dead. Here's one for someone to crack:
(http://i572.photobucket.com/albums/ss166/xonhulu/OR103Elsie5.jpg?t=1264648740)
Cool game...here's one solution:
sqrt[37+sqrt(25)26] = 52/26+2
I'm still getting pictures set up for future use, so someone else can go ahead and post up a new one if they wish.

So you need to have a number present in the previous photo then? OK, how about this one?
(Sorry for the blurry night photo)
(http://members.trainorders.com/android/misc/I25Exit186Signs.jpg)
(261)/((25² + 20²)1000) = 187186

Here's a wicked simple one:
(http://gribblenation.net/meends/7south1.jpg)

(http://gribblenation.net/meends/img_6632.jpg)

(http://gribblenation.net/meends/3wfrom95s2.jpg)
http://gribblenation.net/meends/3wfrom95s2.jpg for fullres  those are exits 112 & 113

(http://gribblenation.net/meends/img_6607.jpg)

(http://gribblenation.net/meends/46s7.jpg)

(http://gribblenation.net/meends/46s7.jpg)
Now, that one's trivial.
3 * 15 + 1 = 46

Cool game...here's one solution:
sqrt[37+sqrt(25)26] = 52/26+2
Good answer. Mine was sqrt(25)sqrt(37262)=52/26

I'll clear out these Mass. signs, if someone else will bring the next picture to the table.
Reply 49 ("wicked simple"): 6 + 16 = 7 + 15
Reply 50 (US 202 intersection): 115  (26 / sqrt(4)) + 100 = 202
Reply 51 (BGS assembly): (8 + sqrt(27/3))/11 = 113  112
Reply 52 (US 202 intersection w/ "To I95" shield): 202 + 4!  26 = 115 + 95  sqrt(100)

Good job on all those!
Here's another photo to try:
(http://i572.photobucket.com/albums/ss166/xonhulu/Oregon%20State%20Routes/OR19Arlington21.jpg?t=1272127716)

Why do so many of these involve Oregon in some way?

Why do so many of these involve Oregon in some way?
I live in Oregon, so naturally most of my photos are from here. Since OR likes putting mileages with control cities along with their shield assemblies, there are a lot of good shots for this game from my state. Makes the equations a little more challenging when you have more numbers to deal with.
I agree, though, let's get some more from other parts of the country. I'd like to solve them more often instead of just submitting.

> I'll clear out these Mass. signs, if someone else will bring the next picture to the table.
Mass? MASS? Aw man, you're killing me! :(
> Reply 49 ("wicked simple"): 6 + 16 = 7 + 15
That was my first solution, quickly followed by 16  15 = 7  6
> Reply 51 (BGS assembly): (8 + sqrt(27/3))/11 = 113  112
You forgot to take the "1 Mile" into account...
> Reply 52 (US 202 intersection w/ "To I95" shield): 202 + 4!  26 = 115 + 95  sqrt(100)
Cool. I came up with 202+4!26 = sqrt(100)*(11595)
And now, another easy one:
(http://yakra.dynosaur.com/roads/mplex/61516150/017_17.jpg)

(http://yakra.dynosaur.com/roads/gallery/madison/img_6698.jpg)

And now, another easy one:
(http://yakra.dynosaur.com/roads/mplex/61516150/017_17.jpg)
You're right on the easy part: 150/15 = 16  6

That one was like instantsolveeasy, but on #57 and #61, I just cannot get them... :banghead:
(I guess I'm asking, you did solve them before posting, right ;) )
In #61, I'm assuming you need to use the 30 on the Speed limit sign as well, since the photo was not cropped to exclude it?
My brain needed a break, so I looked through my sign folder and spotted this local sign and found it a pretty easy one, so I'll throw it in:
(http://members.trainorders.com/android/misc/I25Exit140CasperCheyenneOnRampSign.jpg)

That one was like instantsolveeasy, but on #57 and #61, I just cannot get them...
(I guess I'm asking, you did solve them before posting, right?)
I posted #57, and I did make sure there was a solution. I will admit, though, it took me a bit to find it!
In #61, I'm assuming you need to use the 30 on the Speed limit sign as well, since the photo was not cropped to exclude it?
Actually, we've been interpreting the rules to say that the signs must all belong to a single assembly, even though I'm not 100% sure they say that. Thus, the speed 30 sign should not be used. Here is the link to the rules again if you want to decide for yourself: http://www.roadsignmath.com/rules/
My brain needed a break, so I looked through my sign folder and spotted this local sign and found it a pretty easy one, so I'll throw it in:
(http://members.trainorders.com/android/misc/I25Exit140CasperCheyenneOnRampSign.jpg)
I'll give yours a shot. I haven't really attempted #61 yet, either, so I'll give it a look, too.

That's why I asked  because there have been a couple earlier that had separated signs used. If I was going to post a photo with such ambiguity due to having another sign present, I would just crop the photo to remove the possiblity of a question.
I did look at those rules, but then they started getting into "elegance scoring" stuff and head started to hurt as much as the problems themselves! :spin:

That's why I asked  because there have been a couple earlier that had separated signs used. If I was going to post a photo with such ambiguity due to having another sign present, I would just crop the photo to remove the possiblity of a question.
It was H.B. Elkins who told us the single assembly rule back in post #19, and he's the one who had past experience with the game, so I'm going with what he said. But I agree with you, just crop out other signs to remove all ambiguity.
I did look at those rules, but then they started getting into "elegance scoring" stuff and head started to hurt as much as the problems themselves! :spin:
I have a feeling the original game was/is more serious than what we're playing. Here, no one's keeping score AFAIK.
Anyway, I looked at your photo in #63 for awhile, looking for all sorts of equations involving products, quotients, square roots and factorials, before it finally dawned on me that: 25 + 26 + 59 + 91 = 20 + 87 + 94. C'mon, it's way too hard if it only involves sums! And I don't get any "elegance" points! :(

Dang, that was easier than I thought. I never tried summing that high!
Mine answer was only slightly more complicated  I got 875926 = sqrt(25)  (9491)

Dang, that was easier than I thought. I never tried summing that high!
Mine answer was only slightly more complicated  I got 875926 = sqrt(25)  (9491)
As I said, I didn't see it right away, either. These usually involve more complicated operations.
Case in point: I just cracked #61: 109 + 95  202 = sqrt(11 + sqrt(100)  17)

= sqrt(11 + sqrt(100)  17)
Thanks! I had boiled the equation down to 2 one side and 11, 100 and 17 on the other but could not find a way to make those 3 values come out to 2. And looking at my notes here I now realize why, I always get the squares for 5 and 10 mixed up in my head, so I had 25 wrote down next to 100 as a possibility. No way I could solve it if I can't do the bloody numbers right! (http://www.thesamba.com/vw/forum/images/smiles/eusa_wall.gif)

Don't feel bad: I once graded a PreCalculus test where the student had 1*1 = 43

Bump from 2010
We should probably remove the rule that each photo contains one from the last photo, since we're doing several at a time.
(https://farm5.staticflickr.com/4242/35387604530_5f1c137d84_c.jpg)
(https://farm5.staticflickr.com/4789/40714340301_7fe089257b_c.jpg)
(https://farm5.staticflickr.com/4780/40021106544_d1bb6a25fa_c.jpg)
I did not use factorials in any of these.