Topic: Road Sign Math (Read 23539 times)

xonhulu · « **Reply #25 on:** December 23, 2009, 07:33:26 PM »

Quote from: agentsteel53 on December 23, 2009, 06:53:36 PM

211 + (13/13) + (99/99) - 2 + 11 - 8 = 214

not quite 0 = 0 but still a kinda trivial solution involving the 13/13 and 99/99. nowhere near as impressive as that WW2 era OR-2/US-101 photo!

Thanks for the props on that; it took me quite awhile to figure that one out.

Anyway, here's another which is a little more difficult. I assume these two signs function effectively as one assembly...

agentsteel53 · « **Reply #26 on:** December 23, 2009, 07:36:42 PM »

Quote from: xonhulu on December 23, 2009, 07:33:26 PM

I assume these two signs function effectively as one assembly...

I think that's reasonable, not the extremely anal rules on the RSM site which apparently allowed a submission to hinge on a single structural support bar. Lame.

ctsignguy · « **Reply #27 on:** December 23, 2009, 08:54:50 PM »

@_@ *my head hurts looking at all this....havent done serious math outside my tax returns in DECADES!

THUD!!! X_x!!!

xonhulu · « **Reply #28 on:** December 23, 2009, 09:22:12 PM »

Quote from: ctsignguy on December 23, 2009, 08:54:50 PM

@_@ *my head hurts looking at all this....havent done serious math outside my tax returns in DECADES!

THUD!!! X_x!!!

I know. This is totally unfair: I teach math, so those mental muscles have stayed strong.

Scott5114 · « **Reply #29 on:** December 24, 2009, 05:03:18 AM »

I never had these skills in the first place :\

xonhulu · « **Reply #30 on:** December 24, 2009, 10:13:51 PM »

No takers? It isn't that horrifically hard...

Duke87 · « **Reply #31 on:** December 26, 2009, 01:18:45 AM »

sqrt(197-97)=(26-22)+(68-62)

Not complicated when you look at it. The fact that 197-97 = 100 and all the numbers on top are even is a glaring nudge in the right direction.

This one should be easier:

That's 1, 7, 87, and 95. Go!

SSOWorld · « **Reply #32 on:** December 26, 2009, 01:58:33 AM »

(87+7) = (95-1)

One of the numbers does not get used - and that number is not a route number

xonhulu · « **Reply #33 on:** December 26, 2009, 06:32:48 PM »

You can use them all: 29 + 81 = 66 + 65 + 1 - (10 + 12). Those are the only numbers on the main assembly.

Here's a really hard one also involving US 10 and 12:

O.k., I'm joking. I'm still looking for a good new photo.

xonhulu · « **Reply #34 on:** December 26, 2009, 07:01:24 PM »

All right, here's another. Try to find a solution where you aren't just balancing the identical numbers, there's a more clever equation.

roadfro · « **Reply #35 on:** December 27, 2009, 04:33:47 AM »

My first go at one of these...

120/20 - (16-14) = 120/(16+14)

Unfortunately, I don't have access to any road photos right now as I'm away from my home computer. I invite anyone to post a new photo in my stead.

xonhulu · « **Reply #36 on:** December 27, 2009, 12:34:43 PM »

Good answer, and thanks for sticking with my rules for it!

I'll look for another to post, but it takes awhile, as I have to make sure there is an answer first.

hbelkins · « **Reply #37 on:** December 27, 2009, 03:57:17 PM »

Here's another relatively simple one from I-90 in the Keystone State:

xonhulu · « **Reply #38 on:** December 27, 2009, 04:42:39 PM »

I'd solve it, but I can't do math in Clearview.

Here's another tough one:

njroadhorse · « **Reply #39 on:** December 27, 2009, 05:55:07 PM »

All Clearview jokes aside, 2 x 9 = 18

Try this out:

xonhulu · « **Reply #40 on:** December 27, 2009, 06:30:23 PM »

No answer yet. We are only using the four numbers (9, 57, 301, 501) on the arm, right? I can solve it using the background shields and speed limit as well, but using any numbers in the background wouldn't be following the rules.

I've got a good one to follow this photo ready to go, but I want to solve this one first.

njroadhorse · « **Reply #41 on:** December 28, 2009, 12:19:51 PM »

Quote from: xonhulu on December 27, 2009, 06:30:23 PM

No answer yet. We are only using the four numbers (9, 57, 301, 501) on the arm, right?

Yeah, just the numbers on the arm.

xonhulu · « **Reply #42 on:** December 28, 2009, 08:25:03 PM »

You'll have to show me your solution, NJRoadhorse; I'm stumped!

Here's that photo I was promising. The WA 12 is an error; it should be US 12.

Duke87 · « **Reply #43 on:** December 28, 2009, 11:15:43 PM »

Easy enough. 25+5/5+12-14=44-20

The mast arm one, however, is driving me crazy.

xonhulu · « **Reply #44 on:** December 28, 2009, 11:22:50 PM »

Good job. I'm still stumped on the mast arm problem, too.

WNYroadgeek · « **Reply #45 on:** January 27, 2010, 08:20:25 PM »

15 + 17 = 86 - 54

xonhulu · « **Reply #46 on:** January 27, 2010, 10:20:17 PM »

Glad this thread isn't dead. Here's one for someone to crack:

topay · « **Reply #47 on:** January 28, 2010, 09:42:19 AM »

Quote from: xonhulu on January 27, 2010, 10:20:17 PM

Glad this thread isn't dead. Here's one for someone to crack:

Cool game...here's one solution:
sqrt[37+sqrt(25)-26] = 52/26+2

I'm still getting pictures set up for future use, so someone else can go ahead and post up a new one if they wish.

Android · « **Reply #48 on:** January 28, 2010, 03:29:01 PM »

So you need to have a number present in the previous photo then? OK, how about this one?
(Sorry for the blurry night photo)

(26-1)/((25² + 20²)-1000) = 187-186

yakra · « **Reply #49 on:** January 28, 2010, 07:32:38 PM »

Here's a wicked simple one:

News:

Author Topic: Road Sign Math (Read 23539 times)