Road Sign Math

[xonhulu]

211 + (13/13) + (99/99) - 2 + 11 - 8 = 214

not quite 0 = 0 but still a kinda trivial solution involving the 13/13 and 99/99.  nowhere near as impressive as that WW2 era OR-2/US-101 photo!

Thanks for the props on that; it took me quite awhile to figure that one out.


Anyway, here's another which is a little more difficult.  I assume these two signs function effectively as one assembly...

[agentsteel53]

I assume these two signs function effectively as one assembly...

I think that's reasonable, not the extremely anal rules on the RSM site which apparently allowed a submission to hinge on a single structural support bar.  Lame.

[ctsignguy]

@_@  *my head hurts looking at all this....havent done serious math outside my tax returns in DECADES!   

THUD!!! X_x!!!

[xonhulu]

@_@  *my head hurts looking at all this....havent done serious math outside my tax returns in DECADES!   

THUD!!! X_x!!!

I know.  This is totally unfair: I teach math, so those mental muscles have stayed strong.

[Scott5114]

I never had these skills in the first place :\

[xonhulu]

No takers?  It isn't that horrifically hard...

[Duke87]

sqrt(197-97)=(26-22)+(68-62)

Not complicated when you look at it. The fact that 197-97 = 100 and all the numbers on top are even is a glaring nudge in the right direction.


This one should be easier:

That's 1, 7, 87, and 95. Go!

[SSOWorld]

(87+7) = (95-1)



One of the numbers does not get used - and that number is not a route number

[xonhulu]

You can use them all:  29 + 81 = 66 + 65 + 1 - (10 + 12).  Those are the only numbers on the main assembly.

Here's a really hard one also involving US 10 and 12:



O.k., I'm joking.  I'm still looking for a good new photo.

[xonhulu]

All right, here's another.  Try to find a solution where you aren't just balancing the identical numbers, there's a more clever equation.

[roadfro]

My first go at one of these...

120/20 - (16-14) = 120/(16+14)


Unfortunately, I don't have access to any road photos right now as I'm away from my home computer.  I invite anyone to post a new photo in my stead.

[xonhulu]

Good answer, and thanks for sticking with my rules for it!

I'll look for another to post, but it takes awhile, as I have to make sure there is an answer first.

[hbelkins]

Here's another relatively simple one from I-90 in the Keystone State:

[xonhulu]

I'd solve it, but I can't do math in Clearview.

Here's another tough one:

[njroadhorse]

All Clearview jokes aside, 2 x 9 = 18

Try this out:

[xonhulu]

No answer yet.  We are only using the four numbers (9, 57, 301, 501) on the arm, right?  I can solve it using the background shields and speed limit as well, but using any numbers in the background wouldn't be following the rules.

I've got a good one to follow this photo ready to go, but I want to solve this one first.

[njroadhorse]

No answer yet.  We are only using the four numbers (9, 57, 301, 501) on the arm, right?

Yeah, just the numbers on the arm.

[xonhulu]

You'll have to show me your solution, NJRoadhorse; I'm stumped!

Here's that photo I was promising.  The WA 12 is an error; it should be US 12.

[Duke87]

Easy enough. 25+5/5+12-14=44-20

The mast arm one, however, is driving me crazy.

[xonhulu]

Good job.  I'm still stumped on the mast arm problem, too.

[WNYroadgeek]

15 + 17 = 86 - 54

[xonhulu]

Glad this thread isn't dead.  Here's one for someone to crack:

[topay]

Glad this thread isn't dead.  Here's one for someone to crack:

Cool game...here's one solution:
sqrt[37+sqrt(25)-26] = 52/26+2

I'm still getting pictures set up for future use, so someone else can go ahead and post up a new one if they wish.

[Android]

So you need to have a number present in the previous photo then?  OK, how about this one? 
(Sorry for the blurry night photo)



(26-1)/((25² + 20²)-1000) = 187-186

[yakra]

Here's a wicked simple one: